question on Supernetting

Question

You have the following four contiguous networks:

• $10.0.0.0/24$
• $10.0.1.0/24$
• $10.0.2.0/24$ 
• $10.0.3.0/24$

What is the supernet address that can represent all these networks?

Answer 1

For all these 4 Networks , the NID(Network ID bits) = 24, HID(Host ID bits)=8.

To Supernet all these four network, you have to borrow 2 bits from NID.

After Supernetting, NID = 22 bits and HID = 10 bits.

Network ID of whole Network will be : 10.0.0.0/22